网页To look for the best feasible solution, we can start from an arbitrary point, for example the vertex (0;0). We can then divide the plane into two regions: the set of points whose cost is greater than or equal to the cost of (0;0), that is the set of points such that x 1 + x 2 0, and the set of points of cost lower than the cost of (0;0), that is, 3